If the mth term of an A. P. is and nth term is then show that

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 Multiple Choice QuestionsLong Answer Type

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351.

If the mth term of an A. P. is 1 over straight n and nth term is 1 over straight m then show that its (mn)th term is 1. 


Let x and d be the first term and common difference respectively of the AP, respectively.
Then,
straight m to the power of th space term space equals space 1 over straight n
rightwards double arrow space straight x plus left parenthesis straight n minus 1 right parenthesis straight d space equals space 1 over straight n
straight x space equals 1 over straight n minus left parenthesis straight m minus 1 right parenthesis straight d space.... space left parenthesis 1 right parenthesis
straight n to the power of th space term space equals 1 over straight m
rightwards double arrow straight x space plus left parenthesis straight n minus 1 right parenthesis straight d space equals space 1 over straight m
rightwards double arrow space 1 over straight n space minus space left parenthesis straight m minus 1 right parenthesis straight d space plus left parenthesis straight n minus 1 right parenthesis straight d space equals space 1 over straight m space left parenthesis from space equ space 1 right parenthesis
rightwards double arrow straight d space left parenthesis straight n minus 1 minus straight m plus 1 right parenthesis space equals space 1 over straight m minus 1 over straight n
rightwards double arrow space straight d left parenthesis straight n minus straight m right parenthesis space equals space fraction numerator straight n minus straight m over denominator nm end fraction
space rightwards double arrow space straight d space equals 1 over mn
Putting space value space of space straight d space in space equation space left parenthesis 1 right parenthesis comma space we space have
straight x space equals space 1 over straight n space minus left parenthesis straight m minus 1 right parenthesis 1 over mn
space equals space 1 over straight n minus straight m over mn space plus 1 over mn
therefore space straight t subscript mn space equals straight a space plus space left parenthesis mn minus 1 right parenthesis straight d space equals space 1 over mn space plus space left parenthesis mn minus 1 right parenthesis 1 over mn space equals space 1

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 Multiple Choice QuestionsShort Answer Type

352.

Find the sum of n terms of the series open parentheses 4 minus 1 over straight n close parentheses space plus open parentheses 4 minus 2 over straight n close parentheses space plus open parentheses 4 minus 3 over straight n close parentheses space plus.........

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 Multiple Choice QuestionsLong Answer Type

353.

The ratio of the sums of the first m and first n terms of an A. P. is m2: n2. Show that the ratio of its mth and nth terms is (2m−1):(2n−1). 

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 Multiple Choice QuestionsShort Answer Type

354.

In an AP, if the common difference (d) = –4, and the seventh term (a7) is 4, then find the first term.


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355.

Find the sum of first 8 multiples of 3.


 Multiple Choice QuestionsLong Answer Type

356.

The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7 : 15. Find the numbers.


 Multiple Choice QuestionsMultiple Choice Questions

357.

The common difference of AP 13q. 1-6q3q, 1-12q3q, ........ is;1 1 6q 1 12q, , 3q 3q 3q
... is:

  • q

  • -q

  • -2

  • 2


 Multiple Choice QuestionsShort Answer Type

358.

How many three-digit natural numbers are divisible by 7?


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 Multiple Choice QuestionsLong Answer Type

359.

The sum of first n terms of an AP is 3n2 + 4n. Find the 25th term of this AP.


360.

Find the number of terms of the AP -12, -9, -6,... 12. If 1 is added toeach term of this AP, then find the sum of all terms of the AP thusobtained.


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