The ratio of the sums of the first m and first n terms of an A. P. is m2: n2. Show that the ratio of its mth and nth terms is (2m−1):(2n−1).
In an AP, if the common difference (d) = –4, and the seventh term (a7) is 4, then find the first term.
Find the sum of first 8 multiples of 3.
First 8 multiples of 3 are
3, 6, 9, 12, 15, 18, 21, 24
The above sequence is an A.P.
a = 3, d = 3 and last term l = 24
The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7 : 15. Find the numbers.
Find the number of terms of the AP -12, -9, -6,... 12. If 1 is added toeach term of this AP, then find the sum of all terms of the AP thusobtained.