The ratio of the sums of the first m and first n terms of an A. P. is m2: n2. Show that the ratio of its mth and nth terms is (2m−1):(2n−1).
In an AP, if the common difference (d) = –4, and the seventh term (a7) is 4, then find the first term.
The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7 : 15. Find the numbers.
The sum of first n terms of an AP is 3n2 + 4n. Find the 25th term of this AP.
Find the number of terms of the AP -12, -9, -6,... 12. If 1 is added toeach term of this AP, then find the sum of all terms of the AP thusobtained.