Show that 9n + 1 - 8n - 9 is divisible by 64, whenever n is a
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    Binomial Theorem

    Multiple Choice QuestionsShort Answer Type

    11.

    Find left parenthesis straight a plus straight b right parenthesis to the power of 4 minus left parenthesis straight a minus straight b right parenthesis to the power of 4. then evaluate space space left parenthesis square root of 3 plus square root of 2 right parenthesis to the power of 4 minus left parenthesis square root of 3 minus square root of 2 right parenthesis to the power of 4

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    12.

    Find left parenthesis straight x plus 1 right parenthesis to the power of 5 plus left parenthesis straight x minus 1 right parenthesis to the power of 5 and hence evaluate left parenthesis square root of 2 plus 1 right parenthesis to the power of 5 plus space left parenthesis square root of 2 minus 1 right parenthesis to the power of 5

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    13.

    Simplify: left parenthesis straight x plus 2 straight y right parenthesis to the power of 10 plus left parenthesis straight x minus 2 straight y right parenthesis to the power of 10

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    14. Show that 9n + 1 - 8n - 9 is divisible by 64, whenever n is a positive integer. 

    9 to the power of straight n plus 1 end exponent space equals space left parenthesis 1 plus 8 right parenthesis to the power of straight n plus 1 end exponent
              =<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array) #1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493) #2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs() #3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...') #4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array) #5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array) #6 {main}</pre>
                                                                             space space plus...... plus space straight C presuperscript straight n plus 1 end presuperscript subscript straight n plus 1 end subscript space left parenthesis 8 right parenthesis to the power of straight n plus 1 end exponent

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    rightwards double arrow             9 to the power of straight n plus 1 end exponent space equals space 1 plus 8 straight n plus 8 plus 64 straight k
    where              straight k equals straight C presuperscript straight n plus 1 end presuperscript subscript 2 plus 8 space straight C presuperscript straight n plus 1 end presuperscript subscript 3 plus........... plus 8 to the power of straight n minus 1 end exponent
    rightwards double arrow                      6 to the power of straight n minus 5 straight n equals 25 straight k plus 1
    Hence, 6 to the power of straight n minus 5 straight n leaves a remainder 1 when divided by 25.

                  
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    15. Using Binomial Theorem, prove that 6n - 5n always leaves remainder 1 when divided by 25.
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    16.

    Find the value of space space open parentheses straight a squared plus square root of straight a squared minus 1 end root close parentheses to the power of 4 plus open parentheses straight a squared minus square root of straight a squared minus 1 end root close parentheses to the power of 4

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    17. Find the expansion of (3x2 - 2ax + 3a2)3 using binomial theorem. 
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    18. If a and b are distinct integers, prove that a-b is a factor of an - bn, whenever n is positive integer.
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    19. Find co-efficient of x5 in the expansion of (1 + 3x)6 (1 - x)5
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    20. In the expansion of (x + a)n, sums of odd and even terms are P and Q respectively. 
    Prove that:

    (a) 2 left parenthesis straight P squared plus straight Q squared right parenthesis space equals space left parenthesis straight x plus straight a right parenthesis to the power of 2 straight n end exponent plus left parenthesis straight x minus straight a right parenthesis to the power of 2 straight n end exponent  (b) left parenthesis straight P squared minus straight Q squared right parenthesis space equals space left parenthesis straight x squared minus straight a squared right parenthesis to the power of straight n
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