The middle term in the expansion of ba5 - 5ab12&nb

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 Multiple Choice QuestionsMultiple Choice Questions

221.

The numerically greatest term in the expansion of (3 - 5x)11 when x = 15, is

  • 55 × 39

  • 55 × 36

  • 45 × 39

  • 45 × 36


222.

The number of subsets of {1, 2, 3, ..., 9} containing atleast one odd number is

  • 324

  • 396

  • 496

  • 512


223.

A binary sequence is an array of 0's and 1's. The number of n-digit binary sequences which contain even number of 0's is

  • 2n - 1

  • 2n - 1

  • 2n - 1 - 1

  • 2n


224.

If X is a binomial variate with the range {0, 1, 2, 3, 4, 5, 6} and P(X = 2) = 4P(X = 4), then the parameter p of X is

  • 13

  • 12

  • 23

  • 34


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225.

The number of integral solutions of x1 + x2 + x3 = 0, with x - 5, is :

  • C215

  • C216

  • C217

  • C218


226.

If Cr - 1n = 36, Crn = 84 and  Cr + 1n = 126, then n is equal to

  • 8

  • 9

  • 10

  • 11


227.

Coefficient of xn in the expansion of 1 + a + bx1! + a + bx22! + a + bx33! + ...

  • ea . bnn!

  • b . ann

  • eb . bnn - 1!

  • an . bn - 1n!


228.

The value of C1 - 2 . C2 + 3 . C3 - 4 . C4 + ... where CrCrn will be

  • - 1

  • 1

  • 0

  • None of these


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229.

The middle term in the expansion of ba5 - 5ab12 is

  • C612ba3

  • - C612ba3

  • C712ba5

  • - C712b5a


A.

C612ba3

Given, ba5 - 5ab12Middle term = n2 + 1th term      n is even Tn2 + 1 = Cn2nba5n2 = - 5abn2 T7 = C612ba56- 5ab6           = C612 b6a3a6b3           = C612ba3Hence, middle term is C612ba3.


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230.

The coefficient of x4 in the expansion of (1 + x + x2 + x3)11 is

  • 990

  • 605

  • 810

  • None of these


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