The coefficient of x3y4z5 in the expansion of (xy + yz + xz)

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 Multiple Choice QuestionsMultiple Choice Questions

241.

If 1 - x + 6x21 - x3 = Ax + B1 + x + C1 + x, then A is equal to

  • 1

  • 2

  • 3

  • 4


242.

If the coefficient of (2r + 1)th term and (r + 2)th term in the expansion of (1 + x)43 are equal, then r is equal to :

  • 12

  • 14

  • 16

  • 18


243.

The coefficient of x5 in the expansion of (1 + x2)5(1 + x)4, is

  • 60

  • 50

  • 40

  • 56


244.

The binomial coefficients which are in decreasing order are

  • 15C5, 15C6, 15C7,

  • 15C10 , 15C9 , 15C8

  • 15C6 , 15C7 , 15C8

  • 15C7 , 15C6 , 15C5


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245.

If  x - 4x2 -5x + 6 can be expanded in the ascending power of x, then the coefficient of x3 is

  • - 73648

  • 73648

  • 71648

  • - 71648


246.

Coefficient of x10 in the expansion of (2 + 3x)e- x is

  • - 2610!

  • - 2810!

  • - 3010!

  • - 3210!


247.

If (1 + x)15 = a0 + a1x + ... + a15x15, then r = 115rarar - 1 is equal to

  • 110

  • 115

  • 120

  • 135


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248.

The coefficient of x3y4z5 in the expansion of (xy + yz + xz)6 is

  • 70

  • 60

  • 50

  • None of these


B.

60

We have,xy + yz +zx6 = r + s + t = 66!r!s!t!xyryzszxt                          = r + s + t = 66!r!s!t!xr + tyr + szs + t

If the general term in the above expanssion contains x3y4z5, then

r + t = 3, r + s = 4 and s + t = 5

Also, r + s + t = 6

Solving these equations, we get

r = 1, s = 3, t = 2

 Coefficient ofx3y4z5 = 6!1!3!2! = 6!2!3! = 60


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249.

If x < 12, then the coefficient of xr in the expansion of 1 +2x1 - 2x2, is

  • r2r

  • (2r - 1)2r

  • r22r + 1

  • (2r + 1)2r


250.

The coefficient of xn in 1 - 2xex is :

  • 1 + 2nn!

  • - 1n1 + 2nn!

  • - 1n1 - 2nn!

  • - 1n1 + 4nn!


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