A and B are points on the circle with centre
O. If a chord CD of the circle subtends an angle of 50° at the point A on the circle and ∠BDC = 70°, then ∠BCD equals:
In the given figure, O is the centre of the circle. ABCD is a trapezium in which
AB || DC and ∠ADC = 110°. The measure of ∠ACD is equal to:
2.5 cm
10 cm
Three chords AB, CD and EF of a circle are respectively 3 cm, 3.5 cm and 3.8 cm away from the centre. Then which of the following is correct?
AB < CD < EF