In Fig. , O is the centre of a circle such that diameter AB = 13

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311. A line intersecting a circle in two points is called a ___________.
  • Diameter
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  • Secant
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318.

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319.

In Fig. , O is the centre of a circle such that diameter AB = 13 cm and AC = 12 cm. BC is joined. Find the area of the shaded region. (Take π = 3.14)


In the given figure,


Given,
Diameter, AB= 13 cm
therefore,

Radius of the circle, r =13/2 = 6.5 cm
angle space ACB space is space the space angle space in space the space semi minus circle.
therefore space angle ACB space equals space 90 degree
Now comma space in space increment ACB comma space using space Phythagoras space theorem comma space we space have
AB squared space equals space AC squared plus BC squared
left parenthesis 13 right parenthesis squared space equals space left parenthesis 12 right parenthesis squared plus left parenthesis BC right parenthesis squared
left parenthesis BC right parenthesis squared space equals space left parenthesis 13 right parenthesis squared minus left parenthesis 12 right parenthesis squared space equals space 169 minus 144 space equals space 25
therefore comma
BC space equals space square root of 25 space equals space 5
Now comma space area space of space shaded space region space equals space Area space of space semi space circle space minus Area space of space increment ACB
equals 1 half πr squared minus 1 half straight x space BC space straight x space AC
equals 1 half space straight x space 3.14 straight x space left parenthesis 6.5 right parenthesis squared space minus 1 half space straight x space 5 space straight x space 12
equals 66.33 minus 30
equals 36.33 space cm squared
Thuss comma space the space area space of space the space shaded space region space is space 36.33 space cm squared.

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320.

Prove that the lengths of the tangents drawn from an external point to a circle are equal.

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