In figure, AB and CD are equal chords of a circle whose centre is O. If OM ⊥ AB and ON ⊥ CD, prove that ∠OMN = ∠ONM.
Given: In figure, AB and CD are equal chords of a circle whose centre is O. OM ⊥ AB and ON ⊥ CD.
To Prove: ∠OMN = ∠ONM.
Proof: ∵ Chord AB = Chord CD
∴ OM = ON ...(1)
| ∵ Equal chords of a circle are equidistant from the centre of the circle
In ∆OMN,
OM = ON | From (1)
∴ ∠OMN = ∠ONM.
| Angles opp. to equal sides
AB and CD are equal chords of a circle whose centre is O. When produced, these chords meet at E. Prove that EB = ED and AE = CE.