ABC and ADC are two right triangles with common hypotenuse AC. Prove that ∠CAD = ∠CBD.
Given: In figure, AB = CD. E is the point of intersection of AD and BC.
To Prove: BE = DE and AE = CE.
Proof: In ∆EAB and ∆ECD,
AB = CD Â Â Â | Given
∠B = ∠D
| Angles in the same segment
∠A = ∠C | Angles in the same segment
∴ ∆EAB ≅ ∆ECD    | ASA
∴ BE = DE    | C.P.C.T.
and    AE = CE.    | C.P.C.T.