P and Q are centres of the two circles which intersect at B and

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsShort Answer Type

71. ABC is an isosceles triangle with AB = AC. A circle through B and C intersects AD and AC at D and E respectively. Prove that BC || DE.
191 Views

72. Prove that the circle drawn on any equal side of an isosceles triangle as diameter, bisects the third side.  
169 Views

73.

In the figure, D is the centre of a circle. Prove that
2(∠XZY + ∠YXZ) = ∠XPZ]

399 Views

 Multiple Choice QuestionsLong Answer Type

74. Prove that the opposite angles of an isosceles trapezium are supplementary.
1579 Views

Advertisement
75. In the figure, O is the centre of the circle. BD = OD and CD ⊥ AB. Find ∠CAB.


1184 Views

76. If the bisectors of the opposite angles of a cyclic quadrilateral ABCD intersect the circle circumscribing it at the points P and Q, prove that PQ is a diameter of the circle.
2149 Views

 Multiple Choice QuestionsShort Answer Type

77. If O is the centre of a circle as shown in figure, then prove x + y = z.


183 Views

78.

5. In the given figure, find the values of a, b, c and d. Given that ∠BCD = 43° and ∠BAE = 62°.

329 Views

Advertisement
Advertisement

79. P and Q are centres of the two circles which intersect at B and C. ACD is a straight line. Find the values of x, y, z.



2x = 150°
| The angle subtended by an arc of a circle at the centre is twice the angle subtended by it at any point on the remaining part of the circle
⇒    x = 75°    ...(1)
x + ∠BCD = 180°
| ∵ ACD is a straight line
⇒ 75° + ∠BCD = 180°
⇒    ∠BCD = 105°
∵ BEDC is a cyclic quadrilateral
∴ ∠BCD + ∠BED = 180°
| Opposite angles of a cyclic quadrilateral are supplementary
⇒ 105° + y = 180°
⇒ y = 75°    ...(2)
z = 2y
| The angle subtended by an arc of a circle at the centre is twice the angle subtended by it at any point on the remaining part of the circle
⇒    z = 2 × 75° = 150°    ...(3)

215 Views

Advertisement
80. ABCD is a cylic quadrilateral. If AC bisects both the angles A and C then prove that ∠ABC = 90°. 
170 Views

Advertisement