Find the square root of the following complex numbers :-5 + 12i

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 Multiple Choice QuestionsShort Answer Type

61.

Write the following in the form a + ib.


space space space space space space fraction numerator 1 minus 2 straight i over denominator left parenthesis 2 plus 3 straight i right parenthesis squared end fraction space

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62.

Find the multiplicative inverse of the following complex numbers :

space space space space space space space space space space space 4 minus square root of negative 9 end root

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63.

Find the multiplicative inverse of the following complex numbers :

space space space space space space space space space space space space space space space space fraction numerator left parenthesis 2 plus 3 straight i right parenthesis space left parenthesis 3 space plus 2 straight i right parenthesis over denominator 5 space plus space straight i end fraction 

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64.

Find the multiplicative inverse of :

space space space space space space space space space space space space straight z space equals space cos space straight theta space minus space 1 space sin space straight theta

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65.

Find the multiplicative inverse of :

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#6 {main}</pre>

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66.

Find the square root of the following complex numbers :

-5 + 12i


Let,  space space space space space space space space square root of negative 5 plus 12 straight i end root = x + iy                                                              ....(i)

Squaring both sides, we get

-5 + 12i = (x + iy)2

rightwards double arrow   - 5 + 12i = x2 + i2y2 + 2xyi

rightwards double arrow - 5 + 12i = x2 - y2 + 2xyi                                                               ....(ii)

Equating real and uimaginary parts, we get

            x2 - y2  = -5                                                                        ....(iii)
              2xy = 12                                                                            ....(iv)

rightwards double arrow      4x2y2 = 144 

Also,                    (x2+ y2)2 = ((x2 - y2)2 + 4x2 y2

rightwards double arrow                      (x2+ y2)2 = 25 + 144 = 169

rightwards double arrow                      x2- y2  = 13                                                            ...(v)            

                                                  (∵ x2- ycannot be negative for x, y  space space element ofR)
From (iii) a nd (v), we have

                    x2- y2  = -5
                
                     x2+ y2 = 13
Adding, we get      2x2 = 8 rightwards double arrowx2 = 4 rightwards double arrow x = plus-or-minus 2
When x = 2, from (iii), 2(2) (y) = 12 or y = 3
When x = 2, from (iii), 2(-2)y = 12 or y = -3

Putting in (i)  we have space space space space space space space space square root of negative 5 space plus space 12 straight i end root space space equals space 2 space plus space 3 straight i

or        space space space space space space space space space space space space square root of negative 5 plus 12 straight i end root space equals space minus 2 minus 3 straight i space equals space minus left parenthesis 2 plus 3 straight i right parenthesis

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#6 {main}</pre>
  


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67.

Find the square root of the following complex numbers :

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#6 {main}</pre>

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68.

Verify that   space space space space space space top enclose left parenthesis 2 plus 3 straight i right parenthesis left parenthesis straight i minus 2 straight i right parenthesis end enclose space equals space top enclose left parenthesis 2 plus 3 straight i right parenthesis space end enclose space. space top enclose left parenthesis 1 minus 2 straight i right parenthesis end enclose space space

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69.

Verify that  

space space space space space space space space space space space space space top enclose open parentheses fraction numerator 3 plus 4 straight i over denominator 1 minus 2 straight i end fraction close parentheses end enclose space equals space fraction numerator top enclose open parentheses 3 plus 4 straight i close parentheses end enclose over denominator top enclose open parentheses 1 minus 2 straight i close parentheses end enclose end fraction

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70.

Find the modulus of the following complex numbers :
(2+3i)(1-i)+(3-5i)

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