Let α and β be the distinct roots of ax2 + bx + c = 0, then �

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 Multiple Choice QuestionsMultiple Choice Questions

101.

If the roots of the quadratic equation x2 + px + q = 0 are tan30° and tan15°, respectively then the value of 2 + q − p is

  • 2

  • 3

  • 0

  • 0

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102.

All the values of m for which both roots of the equations x2 − 2mx + m2 − 1 = 0 are greater than −2 but less than 4, lie in the interval

  • −2 < m < 0

  • m > 3

  • −1 < m < 3 

  • −1 < m < 3 

152 Views

103.

If z2 + z + 1 = 0, where z is a complex number, then the value ofopen parentheses straight z plus 1 over straight z close parentheses squared space plus open parentheses straight z squared space plus 1 over straight z squared close parentheses squared space plus open parentheses straight z cubed space plus 1 over straight z cubed close parentheses squared space plus..... open parentheses straight z to the power of 6 plus 1 over straight z to the power of 6 close parentheses squared space is

  • 18

  • 54

  • 6

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104.

If the cube roots of unity are 1, ω, ω2 then the roots of the equation (x – 1)3 + 8 = 0, are

  • -1 , - 1 + 2ω, - 1 - 2ω2

  • -1 , -1, - 1

  • -1 , 1 - 2ω, 1 - 2ω2

  • -1 , 1 - 2ω, 1 - 2ω2

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105.

The value of α for which the sum of the squares of the roots of the equation x2 – (a – 2)x – a – 1 = 0 assume the least value is

  • 1

  • 0

  • 3

  • 3

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106.

If roots of the equation x2 – bx + c = 0 be two consectutive integers, then b2 – 4c equals

  • – 2

  • 3

  • 2

  • 2

170 Views

107.

If the coefficient of x7  open square brackets ax squared space plus open parentheses 1 over bx close parentheses close square brackets to the power of 11in equals the coefficient of x-7 inopen square brackets ax squared space minus open parentheses 1 over bx close parentheses close square brackets to the power of 11then a and b satisfy the relation

  • a – b = 1

  • a + b = 1

  • a/b =1

  • a/b =1

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108.

If z1 and z2 are two non-zero complex numbers such that |z1 + z2| = |z1| + |z2| then argz1 – argz2 is equal to

  • Ï€/2

  • -Ï€

  • 0

  • 0

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109.

Let α and β be the distinct roots of ax2 + bx + c = 0, then limit as straight x rightwards arrow straight alpha of space fraction numerator 1 minus cos space left parenthesis ax squared plus bx plus space straight c right parenthesis over denominator left parenthesis straight x minus straight alpha right parenthesis squared end fraction space is equal to

  • straight a squared over 2 left parenthesis straight alpha minus straight beta right parenthesis squared
  • 0

  • negative straight a squared over 2 left parenthesis straight alpha minus straight beta right parenthesis squared
  • negative straight a squared over 2 left parenthesis straight alpha minus straight beta right parenthesis squared


A.

straight a squared over 2 left parenthesis straight alpha minus straight beta right parenthesis squared
limit as straight x rightwards arrow straight alpha of space fraction numerator 1 minus cos space straight a space left parenthesis straight x minus straight alpha right parenthesis left parenthesis straight x minus straight beta right parenthesis over denominator left parenthesis straight x minus straight alpha right parenthesis squared end fraction space
space equals space limit as straight x rightwards arrow straight alpha of fraction numerator 2 space sin squared space open parentheses straight a begin display style fraction numerator left parenthesis straight x minus straight alpha right parenthesis left parenthesis straight x minus straight beta right parenthesis over denominator 2 end fraction end style close parentheses over denominator left parenthesis straight x minus straight alpha right parenthesis squared end fraction
space equals space limit as straight x rightwards arrow straight alpha of space fraction numerator 2 over denominator left parenthesis straight x minus straight alpha right parenthesis squared end fraction space straight x fraction numerator begin display style sin squared end style begin display style space end style begin display style open parentheses straight a fraction numerator left parenthesis straight x minus straight alpha right parenthesis left parenthesis straight x minus straight beta right parenthesis over denominator 2 end fraction close parentheses end style over denominator begin display style fraction numerator straight a squared space left parenthesis straight x minus straight alpha right parenthesis squared left parenthesis straight x minus straight beta right parenthesis squared over denominator 4 end fraction end style end fraction space straight x space fraction numerator straight a squared space left parenthesis straight x minus straight alpha right parenthesis squared left parenthesis straight x minus straight beta right parenthesis squared over denominator 4 end fraction
space equals space fraction numerator straight a squared left parenthesis straight alpha minus straight beta right parenthesis squared over denominator 2 end fraction
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110.

If x is so small that x3 and higher powers of x may be neglected, then fraction numerator left parenthesis 1 plus straight x right parenthesis to the power of 3 divided by 2 end exponent space minus open parentheses 1 plus begin display style 1 half end style straight x close parentheses cubed over denominator left parenthesis 1 minus straight x right parenthesis to the power of 1 divided by 2 end exponent end fraction spacemay be approximated as

  • 1 minus 3 over 8 straight x squared
  • 3 x 6 plus 3 over 8 straight x squared
  • negative 3 over 8 straight x squared
  • negative 3 over 8 straight x squared
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