Let z = .x + iy, where x and y are real. The  points (x, y)

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

121.

The sum of the coefficients of all odd degree terms in the expansion of x + x3 -15 + x - x3-15, (x>1) is

  • 2

  • -1

  • 0

  • 1


122.

The common chord of the circles x2 + y2 - 4x - 4y = 0 and 2x2+ 2y2 = 32 subtends at the origin an angle equal to

  • π3

  • π4

  • π6

  • π2


123.

The locus of the mid-points of the chords of the circle x2 + y2 + 2x - 2y - 2= 0, which make an angle of 90° at the centre is

  • x2 + y- 2x - 2y = 0

  • x2 + y- 2x + 2y = 0

  • x2 + y+ 2x - 2y = 0

  • x2 + y+ 2x - 2y - 1 = 0


124.

The expression 1 + in1 - in - 2

  • - in + 1

  •  in + 1

  • - 2in + 1

  • 1


Advertisement
Advertisement

125.

Let z = .x + iy, where x and y are real. The  points (x, y) in the X-Y plane for which z + iz - i is purely imaginary, lie on

  • a straight line

  • An ellipse

  • a hyperbola

  • a circle


D.

a circle

z + iz - i = x +iy +ix + iy - i

         = x +(1 +y)ix +(y - 1)i

         = x+y +1ix + (y - 1)i × x - (y - 1)ix - (y - 1)i

         = x2 - x(y - 1) + x(y + 1)i - (y + 1)(y - 1)i2x2 - (y - 1)2i2

         = x2 + i- xy + x + xy + x + y2 - 1x2 + (y - 1)2

         =  x2 + y2 - 1x2 + (y - 1)2 + 2xx2 + (y -1)2i

Now, z + iz - i is purely imaginary.

 Rez + iz - i = 0

 x2 + y2 - 1x2 + (y - 1)2 = 0

 x2 + y2 = 1

 (x, y) lies on a circle.


Advertisement
126.

If p, q are odd integers, then the roots of the equation 2px2 + (2p + q) x + q= 0 are

  • rational

  • irrational

  • non-real

  • equal


127.

If a, b {1, 2, 3} and the equation ax2 + bx + 1 = 0 has real roots, then

  • a > b

  • a  b

  • number of possible ordered pairs (a, b) is 3

  • a<b


128.

The complex number z satisfying the equation z - i = z + 1 = 1 is

  • 0

  • 1 + i

  • - 1 + i

  • 1 - i


Advertisement
129.

If z1 , z2, z3 are imaginary numbers such that z1 = z2 = z3 = 1z1 + 1z2 + 1z3 = 1, then z1 + z2 + z3 is

  • equal to 1

  • less than

  • greater than 1

  • equal to 3


130.

If p.q are the · roots of the equation x2 + px + q =0, then

  • p = 1, q = - 2

  • p = 0, q = 1

  • p = - 2, q = 0

  • p = - 2, q = 1


Advertisement