The number of solution(s) of the equation is/are
2
0
3
1
B.
0
Given equation is
On squaring both sides, we get
Again, squaring both sides, we get
4(x - 1) = 4x2 + 1 - 4x
But, when we put x = in eq.(i), we get
In a , are the roots of pq(x2 + 1) = r2x. Then, is
a right angled triangle
an acute angled triangle
an obtuse angled triangle
an equilateral triangle
Let f(x) = 2x2 + 5x + 1. If we write f(x) as f(x) = a(x + 1)(x - 2) + b(x - 2)(x - 1) + c(x - 1)(x + 1) for real numbers a, b, c then
there are infinite number of choices for a, b, c
only one choice for a but infinite number of choices for b and c
exactly one choice for each of a, b, c
more than one but finite number of choices for a, b, c
If are the roots of ax2 + bx + c = 0 () and are the roots of px2 + qx + r = 0 (p 0), then the ratio of the squares of their discriminants is
a2 : p2
a : p2
a2 : p
a : 2p
Suppose that z1, z2, z3 are three vertices of an equilateral triangle in the Argand plane. Let be a non-zero complex number. The points will be
the vertices of an equilateral triangle
the vertices of an isosceles triangle
collinear
the vertices of a scalene triangle
In the Argand plane, the distinct roots of 1 + z + z3 + z4 = 0 (z is a complex number) represent vertices of
a square
an equilateral triangle
a rhombus
a rectangle
If are the roots of the quadratic equation x2 + px + q = 0, then the values of are respectively
- p(3q - p2) and (p2 - q)(p2 + 3q)
pq - 4 and p4 - q4
3pq - p3 and (p2 - q)(p2 - 3q)