Let f(x) = ax2 + bx + c, g(x) = px2 + qx + r such that f(1)

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 Multiple Choice QuestionsMultiple Choice Questions

161.

Let R be the set of real numbers and the functions f : R ➔ R and g : R ➔ R be defined by f(x) = x2 + 2x - 3 and g(x) = x + 1. Then, the value of x for which f(g(x)) = g(f(x)) is

  • - 1

  • 0

  • 1

  • 2


162.

The maximum value of z, when the complex number z satisfies the condition z + 2z = 2 is

  • 3

  • 3 + 2

  • 3 + 1

  • 3 - 1


163.

If 32 + i3250 = 325x +iy, where x and y are real, then the ordered pair (x, y) is

  • - 3, 0

  • 0, 3

  • 0, - 3

  • 12, 32


164.

If z - 1z + 1 is pure imaginary, then

  • z = 12

  • z = 1

  • z = 2

  • z = 3


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165.

Let f(x) = ax2 + bx + c, g(x) = px2 + qx + r such that f(1) = g(1), f(2) = g(2) and f(3) - g(3) = 2. Then, f(4) - g(4) is

  • 4

  • 5

  • 6

  • 7


C.

6

Given, f(x) = ax2 + bx + c, g(x) = px2 + qx + r 

Since f(1) = g(1)

 a + b + c = p +q + r           ...(i)

f(2) = g(2)

 4a +2b +c = 4p +2q + r     ...(ii)

Subtracting Eq. (ii) from Eq. (i), we get

3a + b = 3p + q                      ...(iii)

f(3) - g(3) = 2

  9a +3b +c - 9p + 3q +r = 2  33a + b + c - 33p + q - r = 2                                             c - r = 2    ...iv

        3a +b = 3p +q

From Eq. (i),

 (a - p) + (b - q) + (c - r) = 0

    a - p + b - q + 2 = 0            ...(v)

From Eq. (ii),

4(a - p) + 2(b - q) + c - r = 0

 2a - p + b - q + 1 = 0            ...(vi)

Subtracting Eq.(v) from Eq. (vi), we get

(a - p) - 1 = 0

        a - p = 1

 From Eq. (v),

      b - q = - 3

Now,

f(4) - g(4) = (16a + 4b + c) - (16p + 4q + r)

               = 16(a - p) + 4(b - q) + (c - r)    ...(vii)

Substituting the values of (a - p), (b - q), (c - r) from above in Eq. (vii), we get

f(4) - g(4) = 16 × 1 + 4- 3 + 2

                = 16 - 12 + 2 = 6


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166.

The equations x2 + x + a= 0 and x2 + ax + 1 = 0 have a common real root

  • for no value of a

  • for exactly one value of a

  • for exactly two value of a

  • for exactly three value of a


167.

The points representing the complex number z for which arg z - 2z + 2 = π3 lie on

  • a circle

  • a straight line

  • an ellipse

  • a parabola


168.

The quadratic equation 2x2 - (a3 + 8a - 1)x + a2 - 4a = 0 posses roots of opposite sign. Then,

  •  0

  • 0 < a < 4

  • 4  a < 8

  • a  8


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169.

If logex2 - 16  loge4x - 11, then

  • 4 < x  5

  • x < - 4 or x > 4

  • - 1 < x  5

  • x < - 1 or x > 5


 Multiple Choice QuestionsShort Answer Type

170.

Determine the sum of imaginary roots of the equation (2x + x - 1) ( 4x2 + 2x - 3) = 6


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