If the complex number z lies on a circle with centre at the origin and radius = , then the 4 complex number - 1 + 8z lies on a circle with radius
4
1
3
2
If the area of the triangle on the complex plane formed by the points z, z + iz and iz is 200, then the value of 3lz I must be equal to
20
40
60
80
A cmplex number z is such that arg. The points representing this complex number will lie on
an ellipse
a parabola
a circle
a straight line
If , then the values of x are
- 2, 2, - 4
- 2, 2, 4
3, 2, - 2
4, 4, 3
B.
- 2, 2, 4
, then
In this case, the equation becomes
x2 - x - 6 = - x - 2
or x2 - 4 = 0
x =
Clearly, x = 2 satisfies the domain of the equation in this case. So, x = 2 is a solution.
Then, equation reduces to x2 - x - 6 = 0 = x + 2 i.e., x2 - 2x - 8 = 0 or x = - 2, 4
Both these values lies in the domain of the equation in this case, so x = - 2, 4 are the roots. Hence, roots are x = - 2, 2, 4
If are the roots of x2 - ax + b = 0 and if = Vn, then
Vn + 1 = aVn + bVn - 1
Vn + 1 = aVn + aVn - 1
Vn + 1 = aVn - bVn - 1
Vn + 1 = aVn - 1 + bVn