If α, β, γ are the 

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 Multiple Choice QuestionsMultiple Choice Questions

291.

The roots of the equation x - 3x - 2 = 0 are

  • - 1, - 1, 2

  • - 1, 1, - 2

  • - 1, 2, - 3

  • - 1, - 1, - 2


292.

If α, β, γ are the roots of x3 + 2x2 - 3x - 1 = 0 then α- 2 + β- 2 + γ- 2 = 

  • 12

  • 13

  • 14

  • 15


293.

If α1, α2, α3 respectively denote the moduli of the complex number - i, 13(1 + i) and - 1 + i, 3 then their increasing order is

  • α1, α2, α3

  • α3, α2, α1

  • α2, α1, α3

  • α3, α1, α2


294.

If α is a  non-real root of x6 = 1, then α5 + α3  + α + 1α2 + 1 is equal to,

  • α2

  • 0

  • - α2

  • α


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295.

The difference between two roots of the equation x3 - 13x2 + 15x + 189 = 0 is 2. Then  the roots of the equation are :

  • - 3, 5, 7

  • - 3, - 7, - 9

  • 3, - 5, 7

  • - 3, - 7, 9


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296.

If α, β, γ are the roots of the equation x3 - 6x2 + 11x + 6 = 0,then  α2β + αβ2 is equal to:

  • 80

  • 84

  • 90

  • - 84


B.

84

 α, β, γ are the roots of the equation x3 - 6x2 + 11x + 6 = 0.                α + β + γ = 6          αβ + βγ + γα = 11and                     αβγ = - 6Now  α2β + αβ2  = α2β + β2γ + γ2α + αβ2  +βγ2 + γα2                                     = αβα + β  +βγβ + γ + γαγ + α                                     = αβ6 - γ  +βγ6 - α + γα6 - β                                     = 6αβ + βγ + γα - 3αβγ                                     = 611 + 36                                     = 66 + 18 = 84


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297.

The locus of the point z = x + iy satisfying the equation

z - 1z + 1 = 1 is given by :

  • x = 0

  • y = 0

  • x = y

  • x + y = 0


298.

The equation of the locus of z such that z + iz - i = 2, where z= x + iy is a complex number, is

  • 3x2 + 3y2 + 10y - 3 = 0

  • 3x2 + 3y2 + 10y + 3 = 0

  • 3x2 - 3y2 - 10y - 3 = 0

  • x2 + y2 - 5y + 3 = 0


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299.

The product of the distinct (2n)th roots of 1 + i3 is equal to :

  • 0

  • - 1 - i3

  • 1 + i3

  • - 1 + i3


300.

If α and β are the roots of the equation ax2 + bx + c = 0 and, if px2 + qx + r = 0 has roots 1 - αα and 1 - ββ, then r is equal to

  • a + 2b

  • a + b + c

  • ab + bc + ca

  • abc


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