Radius, r of the circle = 5 ...(i)
The centre is the point of intersection of straight lines
2x - y - 5=0 and 3x + 2y = 4
Solving these two equations simultaneously, we have
4x - 2y = 10
3x + 2y = 4
Adding, we get 7x = 14 or x = 2
4 - y - 5 = 0 or y = -1
∴ The co-ordinates of the centre are (2, -1)
h = 2, k = -1 and r = 5
The equation of the circle in the standard form is:
or
which is the required equation of the circle.