Let the equation of the circle be ...(i)
It passes through (2, 3) ...(ii)
It passes through (-1, 1) ...(iii)
From (ii) and (iii), we have
...(iv)
Also, centre (h, k) lies on the line x - 3y -11 = 0 h - 3k - 11 = 0 ...(v)
Multiplying (v) by 6, we get
6h - 18k - 66 =0 ...(vi)
Subtracting (vi) from (iv), we get
∴ from (v),
Also, from (ii),
Hence, the equation of circle is:
or or
or
Hence, the equation of circle is: