Draw a line segment of length 7.6 cm and divide it in the ratio

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsShort Answer Type

61.
Construct a right triangle ABC, right angled at B, in which BC = 4 cm and AC + AB = 8 cm.
96 Views

62. Construct a ∆ABC, in which ∠B = 60°, ∠C = 45°and AB + BC + CA = 10 cm.
81 Views

63. Construct AABC with BC = 4 cm, ∠B = 75° and AB + AC = 10 cm.
78 Views

64. Construct AABC with BC = 4 cm, ∠B = 75° and AB + AC = 10 cm.
84 Views

Advertisement
65. Construct a triangle in which base is 4.1 cm, base angle is 45° and sum of other two sides is 6.7 cm.
142 Views

66. Construct a ∆ABC, in which base BC = 4.5 cm, ∠C = 45°and sum of sides AB and AC is 8 cm. Justify your construction.
555 Views

67. Draw AB = 6 cm. Construct an angle of 30° at A and also draw the perpendicular bisector of AB.
132 Views

68. Construct an angle of 52 1 half degree with the help of compass and foot ruler.
90 Views

Advertisement
69. Construct an angle of 37 1 half degree using a ruler and compass.
95 Views

Advertisement

70. Draw a line segment of length 7.6 cm and divide it in the ratio 5 : 8. Measure the two parts.


Steps of Construction :
(i)     Draw AB = 5.6 cm
(ii)    At a draw an acute ∠BAX below base AB.


Steps of Construction :(i)     Draw AB = 5.6 cm(ii)    At a draw

(iii)    On AX make 5 + 8 i.e. 13 equal parts and mark them as A1, A2, A3, A4,... A13

(iv)    Join B to A13. From A5 draw A5C || A13B. C is the required point of division and AC : CB = 5 : 8.

On measuring, we get
AC = 3.1 cm,
CB = 4.5 cm
Justification :

because space space straight A subscript 5 straight C space space space space parallel to space space space straight A subscript 13 straight B
therefore space space space fraction numerator AA subscript 5 over denominator straight A subscript 5 straight A subscript 13 end fraction space equals space AC over CB space
space space

[Using basic proportionally theorem]

But space space space space space fraction numerator AA subscript 5 over denominator straight A subscript 5 straight A subscript 13 end fraction space equals space 5 over 8 space

Therefore,    AC over CB space equals space 5 over 8 space

This shows that C divides AB in the ratio 5 : 8.

2128 Views

Advertisement
Advertisement