Short Answer Type
of the corresponding sides of the first triangle.
of the corresponding sides of the first triangle.
times the corres ponding sides of the isosceles triangle.
Step of Construction :
(i) Draw a line segment BC = 8 cm.
(ii) Draw a perpendicular bisector AD (4 cm) of BC.
(iii) Joining AB and AC we get isosceles ΔABC.
(iv) Construct an acute ∠CBX downwards.
(v) Along BX mark off 3 equal points B1, B2, B3 such that BB1 = B1B2 = B2B3.
(vi) Join C to B2 and draw a line through B3 parallel to B2C intersecting the extended line segment BC at C’.
(vii) Again draw a parallel line C’ A’ to AC cutting BP at A’.
(viii) ΔA ‘BC’ is the required triangle.
Justification :
C’A’ || CA [By construction] ΔABC ~ ΔA ‘BC’
[Using AA similarity condition]
of the corresponding sides of the triangle ABC.
Long Answer Type
times the corresponding sides of the given triangle.
Short Answer Type
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