Steps of Construction :
(i) Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and ∠ABC = 60°.
(ii) Draw any ray BX making an acute angle with BC on the side opposite to the vertex A.
(iii) Along BX, mark off 4 points B1, B2, B3 and B4 on BX such that BB1 = B1B2 = B2 B3 = B3B4.
(iv) Join B4C and draw a line through B3 parallel to B4 C intersecting BC to C’.
(v) Draw a line through C’ parallel to the line CA to intersect BA at A’.
Then A ‘BC’ is the required triangle. Justification :
[By the Basic Proportionality Theorem]