Steps of Construction :
(i) Draw line BC = 4 cm.
(ii) Draw BA = 3 cm line segment with 90° at B.
(iii) Join AC to form right ΔABC.
(iv) Construct an acute ∠CBX downwards.
(v) Along BX mark off 5 equal points B1, B2, B3, B4, B5 such that BB1 = B1B2=... = B4B5.
(vi) Join C to B3 and draw a line through B5 parallel to B3C intersecting the extended line segment BC at C’.
(vii) Again we draw C’A’ parallel to AC.Thus, ΔA‘BC’ is the required triangle.
Justification :