82. Let ABC be a right angle in which AB = 6 cm, BC = 8 cm and ∠B = 90°. BD is the perpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.

Steps of Construction :
(i).    Draw line segments BC = 4 cm and AB = 3 cm perpendicular to each other. Join AC. ΔABC is the right triangle.
(ii)    Taking mid-point E of BC as centre, draw a circle with radius 2 cm, passing through B, C and D.
at B, i.e. AB ⊥ BC.
Its length AB = 3 cm.
Taking centre A, draw an arc of 3 cm (AB = AF) cutting the circle at F.
Join AF. AF and AB are the required tangents.