(i) Draw AB = 6 cm.
(ii) Draw a ray AX making an acute ∠ BAX.
(iii) Along AX, mark points A1, A2, A3 ..., A7, such that AA1 = A1A2.........= A6A7.
(iv) Join A7B.
(v) Through A3 draw a line A3C ||A7B intersecting AB at C.
Thus, points C so obtained is the required point which divides internally in the ratio 3 : 4.