88. Construct a ΔPBC, similar to a given ΔPQR, with QR = 6 cm, PR = PQ = 5 cm, such that each of its side is 5/7th of the corresponding sides of the ΔPQR.

Steps of Construction :

(i)    Construct a ΔPQR in which PR = PQ = 5 cm and QR = 6cm.
(ii)    At P draw an acute ∠QPX, below base PQ.
(iii)    Along PX, mark off
P₁, P₂, P₃,..., P₆,P₇.
(iv)    Join P₇Q.
(v)    From P₅ draw P₅B || P₇Q meeting PQ at B.
(vi)    From B, draw BC || RQ meeting PR at C.
Thus ΔPBC is the required triangle, each of whose sides is  of the corresponding sides of the ΔPQR.