89. Draw a ΔABC in which BC = 6 cm, AB = 4 cm and AC = 5 cm. Draw a triangle similar to ΔABC with its sides equal to 3/4th of the corresponding sides of ΔABC.

Steps of Construction :

(i)    Construct a triangle ABC in which BC = 6 cm, AB = 4 cm and AC = 5 cm.
(ii)    At B draw an acute ∠CBX below base BC.
(iii)    Along BX, mark off points B₁, B₂, B₃, B₄, such that BB₁ = B₁B₂ = B₂B₃ = B₃B₄.
(iv)    Join B₄C.
(v) From B₃ draw B₃C’ || B₄C meeting BC at C’.
(vi) From C’ draw C’ A’ || CA, meeting AB at A’. Thus A ‘BC’ is the required triangle each of whose sides is 3 / 4th of the corresponding sides of ΔABC