Steps of Construction :
1. Draw a line segment AB = 5 cm.
2. At A make ∠BAY = 45°.
3. Take A as centre and radius = AC = 6 cm (= CA), draw an arc cutting AY at C.
4. Join BC to obtain the triangle ABC.
5. Draw any ray AX making an acute angle with AB on the side opposite to the vertex
C.
6. Mark off 6 points (the greater of 6 and 5 in 6/5) A1, A1, A3, A4,A5 and A6 on AX so
that
AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6
7. Join A5 (the 5th point, being the smaller of 5 and 6 in 5/6) to B and draw a line through A6 parallel to A5B intersecting the extended line segment AB at B’.
8. Draw a line through B‘C’ parallel to BC intersecting the extended line segment AC at C’.
Thus, AB ‘C’ is the required triangle
Construct a triangle similar to given ABC in which AB = 4 cm, BC = 6 cm and ∠ABC = 60°, such that each side of the new triangle is 3/4 of given Δ ABC.
Draw a line segment 4.5 cm long and divide it internally in the ratio 2 : 3. Measure each part.