Construct a triangle similar to given ABC in which AB = 4 cm, BC = 6 cm and ∠ABC = 60°, such that each side of the new triangle is 3/4 of given Δ ABC.
Steps of Construction:
(i) Construct a ΔABC in which AB = 6.5 cm, ∠B = 60°, BC = 5.5 cm.
(ii) At B draw an acute angle CBX below base BC.
(iii) Along BX, mark off points B1, B2, B3, such that BB1 = B1 B2 = B2 B3.
(iv) Join B2C.
(v) From B3 draw B3C’ || B2C meeting produced part of BC at C.
(vi) From C’, draw C’ A’ || C A intersecting the extended line segment BA at A’.
Thus, A’B’C’ is the required triangle each of whose sides is 3/2 times the corresponding sides of the triangle ΔABC.
Construction Based on tangent to a circle
Draw a line segment 4.5 cm long and divide it internally in the ratio 2 : 3. Measure each part.