Steps of Construction
1. Draw a line segment AB = 5 cm.
2. Taking A as centre and some radius, draw an arc of a circle, which intersects AB, say at a point P.
3. Taking P as centre and with the same radius as before, drawn an arc intersecting the previously draw arc, say at a point E.
4. Draw the ray AC passing through E.
5. From ray AC, cut off AD = 6 cm.
Then, ∠DAB is the required angle of 60° such that AD = 6 cm.
6. Now, taking A and D as centres and radius more than AD, draw arcs on both sides of the line segment AD (to intersect each other).
7. Let these arcs intersect each other at M and N. Join MN.
8. Let MN intersect AD at the point L. Then line MLN is the required perpendicular bisect or of AD.