Given: In AABC, BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.
Required: To construct the triangle ABC.
Steps of Construction:
1. Draw the base BC = 7 cm.
2. At the point B make an angle XBC = 75°.
3. Cut a line segment BD equal to AB + AC (= 13 cm) from the ray BX.
4. Join DC.
5. Make an ∠DCY = ∠BDC.
6. Let CY intersect BX at A.
Then, ABC is the required triangle.