Given: In ∆ABC, BC = 8 cm, ∠B = 45° and AB – AC = 3.5 cm.
Required: To construct the triangle ABC.
Steps of Construction:
1. Draw the base BC = 8 cm.
2. At the point B make an angle XBC = 45°.
3. Cut the line segment BD equal to AB – AC (= 3.5 cm) from the ray BX.
4. Join DC.
5. Draw the perpendicular bisector, say PQ of DC.
6. Let it intersect BX at a point A.
7. Join AC.
Then, ABC is the required triangle.