Important Questions of Continuity and Differentiability Mathematics | Zigya

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 Multiple Choice QuestionsLong Answer Type

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41. The function straight f left parenthesis straight x right parenthesis equals fraction numerator log left parenthesis 1 plus ax right parenthesis minus log left parenthesis 1 minus bx right parenthesis over denominator straight x end fractionis not defined at x = 0. Find the value of/(x) so that f is continuous at x = 0.
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 Multiple Choice QuestionsShort Answer Type

42. Discuss continuity of f(x) at x = 0, if
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator log left parenthesis 1 plus ax right parenthesis minus log left parenthesis 1 minus bx right parenthesis over denominator straight x end fraction comma space straight x not equal to 0 end cell row cell space space space space space space space space space space space space space space space space space space space straight a plus straight b space space space space space space space space space space space space space space space space space space space comma space straight x equals 0 end cell end table close
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43. Discuss continuity of f(x) at x = 0, if
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell 1 over straight x plus fraction numerator log left parenthesis 1 minus straight x right parenthesis over denominator straight x squared end fraction comma space space if space straight x not equal to 0 end cell row cell space space space space space space space space minus 1 half space space space space space space space space space space space space space comma space if space straight x equals 0 end cell end table close
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44. Discuss continuity of f(x) at x = 0, if
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator straight e to the power of straight x minus 1 minus straight x over denominator straight x squared end fraction comma space if space straight x not equal to end cell row cell space space space space space space 1 half space space space space space space space space space comma space if space straight x equals 0 end cell end table close
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45. Find k so that
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator straight x squared minus 25 over denominator straight x minus 5 end fraction comma space if space straight x not equal to 5 end cell row cell space space space space space space space straight k space space space space space space space comma space if space straight x equals 5 end cell end table close
is continous at x=5.
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46. Determine k, so that
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator straight x squared minus 36 over denominator straight x minus 6 end fraction comma space if space straight x not equal to 6 end cell row cell space space space space space space space straight k space space space space space space space comma space if space straight x equals 6 end cell end table close
is continuous at x = 6.
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47. Determine the value of the constant k so that the function
straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator straight x squared minus 3 straight x plus 2 over denominator straight x minus 1 end fraction comma space if space straight x not equal to 1 end cell row cell space space space space space space space space space space straight k space space space space space space space space space comma space if space straight x equals 1 end cell end table close
is continous at x=1.
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48. Determine the value of k so that the function

straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator straight x squared minus 9 over denominator straight x minus 3 end fraction comma space straight x not equal to 1 end cell row cell space space space space space space straight k space space space space space comma space straight x equals 3 end cell end table close
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49. For what value of k is the function

straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator sin space 5 straight x over denominator 3 straight x end fraction comma space if space straight x not equal to 0 end cell row cell space space space space space space straight k space space space space space space comma space if space straight x equals 0 end cell end table close
continous space at space straight x equals 0 ?
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50. Determine the value of the constant k so that the function

straight f left parenthesis straight x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell fraction numerator sin space 2 straight x over denominator 5 straight x end fraction comma space if space straight x not equal to 0 end cell row cell space space space space space space space straight k space space space space space comma space if space straight x equals 0 end cell end table close
is space continous space at space straight x equals 0
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