Prove that the function f(x) = 5 x – 3 is continuous at x = 0,

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 Multiple Choice QuestionsShort Answer Type

1. Check the continuity of the function f given by f(x) = 2 x + 3 at x = 1.
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 Multiple Choice QuestionsLong Answer Type

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2. Prove that the function f(x) = 5 x – 3 is continuous at x = 0, at x  = – 3 and at x = 5.


Here space straight f left parenthesis straight x right parenthesis equals 5 straight x minus 3
left parenthesis straight i right parenthesis space Lt with straight x rightwards arrow 0 below space straight f left parenthesis straight x right parenthesis equals stack space Lt with straight x rightwards arrow 0 below space left parenthesis 5 straight x minus 3 right parenthesis equals 5 left parenthesis 0 right parenthesis minus 3 equals 0 minus 3 equals negative 3
Now space space straight f space is space defined space at space straight x equals 0
and space space straight f left parenthesis 0 right parenthesis equals 5 left parenthesis 0 right parenthesis minus 3 equals 0 minus 3 equals negative 3
therefore space Lt with straight x rightwards arrow 0 below space straight f left parenthesis straight x right parenthesis equals space straight f left parenthesis 0 right parenthesis equals negative 3
therefore space straight f space is space continous space at space straight x equals 0.

left parenthesis ii right parenthesis space stack Lt space with straight x rightwards arrow negative 3 below space straight f left parenthesis straight x right parenthesis equals stack space Lt with straight x rightwards arrow negative 3 below space left parenthesis 5 straight x minus 3 right parenthesis equals 5 left parenthesis negative 3 right parenthesis minus 3 equals negative 15 minus 3 equals negative 18
Now space straight f space is space defined space at space straight x equals negative 3
and space space straight f left parenthesis negative 3 right parenthesis equals 5 left parenthesis negative 3 right parenthesis minus 3 equals negative 15 minus 3 equals negative 18
therefore stack space Lt space with straight x rightwards arrow negative 3 below space straight f left parenthesis straight x right parenthesis equals straight f left parenthesis negative 3 right parenthesis equals negative 18
therefore space straight f space is space continous space at space straight x equals negative 3.

left parenthesis iii right parenthesis stack space Lt space with straight x rightwards arrow 5 below straight f left parenthesis straight x right parenthesis equals stack space Lt with straight x rightwards arrow 5 below space left parenthesis 5 straight x minus 3 right parenthesis equals 5 left parenthesis 5 right parenthesis minus 3 equals 25 minus 3 equals 22
Now space straight f space is space defined space at space straight x equals 5
and space space straight f left parenthesis 5 right parenthesis equals 5 left parenthesis 5 right parenthesis minus 3 equals 25 minus 3 equals 22
therefore Lt with straight x rightwards arrow 5 below space straight f left parenthesis straight x right parenthesis equals straight f left parenthesis 5 right parenthesis equals 22
therefore straight f space is space continous space at space straight x equals 5.
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 Multiple Choice QuestionsShort Answer Type

3. Examine the continuity of the function f(x) = 2x2 –1 at.x = 3
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4. Prove that the function f(x) = xn is continuous at x = n, where n is a positive integer.
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5. Examine whether the function f given by f(x) = x2 is continuous at x = 0.
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6. Is the function defined by f(x) = x2 –sin x + 5 continuous at x =?
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7.

Discuss the continuity of the function f given by f(x) = | x | at x = 0.

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8. Prove that the identity function on real numbers given by f(x) = x is continuous at every real number.
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9. Show that the function defined by g(x) = x – [x] is discontinuous at all integral points. Here [x] denotes the greatest integer less than or equal to x
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10. Find all the points of discontinuity of the greatest integer function defined by f(x) = [x], where [x] denotes the greatest integer less than or equal to x.
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