Differentiate the following w.r.t.x:  from Mathematics Continu

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 Multiple Choice QuestionsShort Answer Type

391. Differentiate the following functions w.r.t. x : left parenthesis straight x space cos space straight x right parenthesis to the power of straight x plus left parenthesis straight x space sin space straight x right parenthesis to the power of 1 over straight x end exponent
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392. Differentiate the following functions w.r.t. x :straight e to the power of sin space straight x end exponent plus left parenthesis tan space straight x right parenthesis to the power of straight x
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393. Differentiate the following functions w.r.t. x :left parenthesis sin space straight x right parenthesis to the power of tan space space straight x end exponent plus left parenthesis cos space straight x right parenthesis to the power of sec space straight x end exponent
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394. Differentiate the following functions w.r.t. x : straight x to the power of tan space straight x end exponent plus left parenthesis sin space straight x right parenthesis to the power of cos space straight x end exponent
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395. Differentiate the following functions w.r.t. x :straight x to the power of straight x to the power of straight x end exponent plus straight x to the power of sin space straight x end exponent
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396. If x=sec ө-cos ө, y=secnө-cosn ө then show that left parenthesis straight x squared plus 4 right parenthesis open parentheses dy over dx close parentheses squared equals straight n squared open parentheses straight y squared plus 4 close parentheses
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397. Differentiate sin-1(ex) w.r.t.x.
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398. Differentiate the following w.r.t.x:sin to the power of negative 1 end exponent left parenthesis straight x square root of straight x right parenthesis comma space 0 less or equal than straight x less or equal than 1
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399. Differentiate the following w.r.t.x: straight e to the power of sin to the power of negative 1 end exponent straight x end exponent


Let space space space space space straight y equals straight e to the power of sin to the power of negative 1 end exponent straight x end exponent
therefore space dy over dx equals straight e to the power of sin to the power of negative 1 end exponent straight x end exponent straight d over dx left parenthesis sin to the power of negative 1 end exponent straight x right parenthesis equals straight e to the power of sin to the power of negative 1 end exponent straight x end exponent. fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction equals fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction. straight e to the power of sin to the power of negative 1 end exponent straight x end exponent
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400. Differentiate the following w.r.t.x:straight e to the power of cos minus 1 left parenthesis straight x plus 1 right parenthesis end exponent
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