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Continuity and Differentiability

Short Answer Type

411. Differentiate the following functions w.r.t.x: $space fraction numerator sin to the power of negative 1 end exponent straight x over denominator square root of 1 minus straight x squared end root end fraction$

Let space space space space space straight y equals fraction numerator sin to the power of negative 1 end exponent straight x over denominator square root of 1 minus straight x squared end root end fraction therefore space dy over dx equals fraction numerator square root of 1 minus straight x squared end root begin display style straight d over dx end style left parenthesis sin to the power of negative 1 end exponent right parenthesis minus left parenthesis sin to the power of negative 1 end exponent right parenthesis. begin display style straight d over dx end style left parenthesis square root of 1 minus straight x squared end root right parenthesis over denominator left parenthesis square root of 1 minus straight x squared end root right parenthesis squared end fraction space space space space space space space space space space space space space equals fraction numerator square root of 1 minus straight x squared end root. begin display style fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction end style minus left parenthesis sin to the power of negative 1 end exponent right parenthesis cross times begin display style fraction numerator negative 2 straight x over denominator 2 square root of 1 minus straight x squared end root end fraction end style over denominator 1 minus straight x squared end fraction space space space space space space space space space space space space space equals fraction numerator 1 plus begin display style fraction numerator straight x space sin to the power of negative 1 end exponent straight x over denominator square root of 1 minus straight x squared end root end fraction end style over denominator 1 minus straight x squared end fraction equals fraction numerator square root of 1 minus straight x squared end root plus straight x space sin to the power of negative 1 end exponent straight x over denominator left parenthesis 1 minus straight x squared right parenthesis to the power of bevelled 3 over 2 end exponent end fraction

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412. Differentiate the following functions w.r.t.x:

cos to the power of negative 1 end exponent square root of fraction numerator 1 plus straight x over denominator 2 end fraction end root

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413. Differentiate the following functions w.r.t.x:

sin to the power of negative 1 end exponent square root of fraction numerator 1 plus straight x squared over denominator 2 end fraction end root

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414. Differentiate the following functions w.r.t.x:

sin to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator square root of 1 plus straight x squared end root end fraction close parentheses

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415. Differentiate the following functions w.r.t.x

fraction numerator cos left parenthesis log space straight x right parenthesis plus tan to the power of negative 1 end exponent straight x over denominator straight e to the power of straight x end fraction

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416. Differentiate the following functions w.r.t.x:

fraction numerator straight e to the power of straight x squared end exponent space tan to the power of negative 1 end exponent straight x over denominator square root of 1 plus straight x squared end root end fraction

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417. Differentiate the following functions w.r.t.x:

fraction numerator cos to the power of negative 1 end exponent begin display style straight x over 2 end style over denominator square root of 2 straight x plus 7 end root end fraction comma space minus 2 less than straight x less than 2

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418. Differentiate :

fraction numerator straight x space cos to the power of negative 1 end exponent straight x over denominator square root of 1 minus straight x squared end root end fraction comma space straight x not equal to 1 comma space straight w. straight r. straight t. straight x

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419.

Prove space that space cot to the power of negative 1 end exponent straight x space plus space cot minus 1 space 1 over straight x space is space constant.

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420.

If space straight y equals fraction numerator 2 over denominator square root of straight a squared minus straight b squared end root end fraction tan to the power of negative 1 end exponent open parentheses square root of fraction numerator straight a minus straight b over denominator straight a plus straight b end fraction end root tan straight x over 2 close parentheses comma space prove space that space dy over dx equals fraction numerator 1 over denominator straight a plus straight b space cos space straight x end fraction comma space straight a greater than straight b greater than 0.

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