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Continuity and Differentiability

Short Answer Type

421.

Differentiate space straight w. straight r. straight t. straight x colon space straight y equals sin to the power of negative 1 end exponent open parentheses fraction numerator 1 plus 2 sin space straight x over denominator 2 plus cos space straight x end fraction close parentheses

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422.

Differentiate space sin to the power of negative 1 end exponent open parentheses fraction numerator straight a plus straight b space cos space straight x over denominator straight b plus straight a space cos space straight x end fraction close parentheses space straight w. straight r. straight t. straight x comma space using space chain space rule

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423.

Prove space that space straight d over straight d open square brackets square root of 1 minus straight x squared end root sin to the power of negative 1 end exponent straight x minus straight x close square brackets equals negative fraction numerator straight x space sin to the power of negative 1 end exponent straight x over denominator square root of 1 minus straight x squared end root end fraction

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424. $Prove space that space straight d over dx left square bracket 2 straight x space tan to the power of negative 1 end exponent straight x minus log left parenthesis 1 plus straight x squared right parenthesis right square bracket equals 2 space tan to the power of negative 1 end exponent straight x.$

straight L. straight H. straight S. space equals straight d over dx left square bracket 2 straight x space tan to the power of negative 1 end exponent straight x minus log left parenthesis 1 plus straight x squared right parenthesis right square bracket space space space space space space space space space space space space space equals straight d over dx left parenthesis 2 straight x space tan to the power of negative 1 end exponent straight x right parenthesis minus straight d over dx left square bracket log left parenthesis 1 plus straight x squared right parenthesis right square bracket space space space space space space space space space space space space space equals 2 straight d over dx left parenthesis straight x space tan to the power of negative 1 end exponent straight x right parenthesis minus fraction numerator 1 over denominator 1 plus straight x squared end fraction. straight d over dx left parenthesis 1 plus straight x squared right parenthesis space space space space space space space space space space space space space equals 2 open square brackets straight x straight d over dx left parenthesis tan to the power of negative 1 end exponent straight x right parenthesis plus space tan to the power of negative 1 end exponent straight x. straight d over dx left parenthesis straight x right parenthesis close square brackets minus fraction numerator 1 over denominator 1 plus straight x squared end fraction.2 straight x equals 2 open square brackets straight x. fraction numerator 1 over denominator 1 plus straight x squared end fraction plus space tan to the power of negative 1 end exponent straight x.1 close square brackets minus fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction equals fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction plus 2 space tan to the power of negative 1 end exponent straight x minus fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction equals 2 space tan to the power of negative 1 end exponent straight x equals straight R. straight H. straight S.

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425.

Prove space that space straight d over dx open square brackets straight x over 2 square root of straight a squared minus straight x squared end root plus straight a squared over 2 sin to the power of negative 1 end exponent straight x over straight a close square brackets equals square root of straight a squared minus straight x squared end root

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426.

Differerntiate space cos to the power of negative 1 end exponent open parentheses fraction numerator 3 cos space straight x minus 4 sin space straight x over denominator 5 end fraction close parentheses space straight w. straight r. straight t. straight x.

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427.

Find space dy over dx space if space straight y equals sin to the power of negative 1 end exponent open parentheses fraction numerator 5 straight x plus 12 square root of 1 minus straight x squared end root over denominator 13 end fraction close parentheses

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428.

If space straight y equals sec to the power of negative 1 end exponent open parentheses fraction numerator straight x plus 1 over denominator straight x minus 1 end fraction close parentheses plus sin to the power of negative 1 end exponent open parentheses fraction numerator straight x plus 1 over denominator straight x minus 1 end fraction close parentheses comma space find space dy over dx.

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429. Differentiate the following w.r.t.x:

tan to the power of negative 1 end exponent open square brackets open parentheses fraction numerator 1 minus cos space straight x over denominator 1 plus cos space straight x end fraction close parentheses to the power of 1 half end exponent close square brackets

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430. Differentiate the following w.r.t.x:

tan to the power of negative 1 end exponent open parentheses square root of fraction numerator 1 plus sin space straight x over denominator 1 minus sin space straight x end fraction end root close parentheses

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