from Mathematics Continuity and Differentiability

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 Multiple Choice QuestionsShort Answer Type

491. Differentiate space tan to the power of negative 1 end exponent open parentheses fraction numerator 2 straight x over denominator 1 minus straight x squared end fraction close parentheses space straight w. straight r. straight t. space sin to the power of negative 1 end exponent open parentheses fraction numerator 2 straight x over denominator 1 plus straight x squared end fraction close parentheses.
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492. Differentiate space tan to the power of negative 1 end exponent open parentheses fraction numerator 3 straight x minus straight x cubed over denominator 1 minus 3 straight x squared end fraction close parentheses space straight w. straight r. straight t. space tan to the power of negative 1 end exponent open parentheses fraction numerator straight x over denominator square root of 1 minus straight x squared end root end fraction close parentheses
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493.  Prove that the derivative of tan-1 open parentheses fraction numerator square root of 1 plus straight x squared end root minus 1 over denominator straight x end fraction close parenthesesw.r.t. tan-1 x is independent of x.
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494. Find space the space derivative space of space tan to the power of negative 1 end exponent fraction numerator 2 straight x over denominator 1 minus straight x squared end fraction space straight w. straight r. straight t. space tan to the power of negative 1 end exponent straight x
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495. Differentiate space sec to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator 2 straight x squared minus 1 end fraction close parentheses space straight w. straight r. straight t. space sin to the power of negative 1 end exponent left parenthesis 3 straight x minus 4 straight x cubed right parenthesis.
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496. Differentiate space sin to the power of negative 1 end exponent straight x space straight w. straight r. straight t. space cos to the power of negative 1 end exponent square root of 1 minus straight x squared end root.
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497. Differentiate space sin to the power of negative 1 end exponent open parentheses fraction numerator 1 minus straight x over denominator 1 plus straight x end fraction close parentheses space straight w. straight r. straight t. space square root of straight x
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498. Differentiate space cos to the power of negative 1 end exponent straight theta space straight w. straight r. straight t. space log left parenthesis 1 plus straight theta right parenthesis


Let space space space space space straight y equals cos to the power of negative 1 end exponent straight theta comma space straight u equals log left parenthesis 1 plus straight theta right parenthesis
therefore space dy over dx equals negative fraction numerator 1 over denominator square root of 1 minus straight theta squared end root end fraction comma space du over dx equals fraction numerator 1 over denominator 1 plus straight theta end fraction
Now space dy over du equals fraction numerator begin display style dy over dθ end style over denominator begin display style du over dθ end style end fraction equals negative fraction numerator 1 over denominator square root of 1 minus straight theta squared end root end fraction cross times fraction numerator 1 plus straight theta over denominator 1 end fraction equals negative fraction numerator 1 plus straight theta over denominator square root of 1 minus straight theta squared end root end fraction
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499. Differentiate space sin to the power of negative 1 end exponent straight theta space straight w. straight r. straight t. space log left parenthesis 1 plus straight theta right parenthesis
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500. Differentiate space log left parenthesis 1 plus straight theta right parenthesis space straight w. straight r. straight t. space sin to the power of negative 1 end exponent space straight theta
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