If Then, the value of the pair (a, b) for which f(x) cannot be continuous at x = 1, is
(2, 0)
(1, - 1)
(4, 2)
(1, 1)
Which of the following function is not differentiable at x = 1 ?
f(x) =
f(x) =
f(x) =
None of the above
Using Rolle's theorem, the equation a0xn + a1xn - 1 + ... + an = 0 has atleast one root between 0 and 1, if
na0 + (n - 1)a1 + ... + an - 1 = 0
D.
Consider the function f defined by
Since, f(x) is a polynomial, so it is continuous and differentiable for all x.
Consequently, f(x) is continuous in the closed interval [0, 1] and differentiable in the open interval (0, 1).
Also, f(0) = 0
i.e. f(0) = f(1)
Thus, all the three conditions of Rolle's theorem are satisfied. Hence, there is atleast one value of x in the open interval (0, 1), where f'(x) = 0
i.e. a0xn + a1xn - 1 + ... + an = 0
The value of cfrom the Lagrange's mean value theorem for which f(x) = in [1, 5], is
5
1
None of these
Let f'(x), be differentiable a. If f(1) = - 2 and f'(x) 2 x [1, 6], then
f(6) < 8
f(6) 8
f(6) 5
f(6) 5