If the derivative of the function f(x) is every where continuous and is given by

$$\begin{gathered} \mathrm{f}\left(\mathrm{x}\right) = \left\{{\mathrm{bx}}^2 + \mathrm{ax} + 4; \mathrm{x} \ge - 1 \\ {\mathrm{ax}}^2 + \mathrm{b}; \mathrm{x} < - 1\right\} \end{gathered}$$, then :

• a = 2, b = - 3

• a = 3, b = 2

• a = - 2, b = - 3

• a = - 3, b = - 2

If f(x + y) = f(x)f(y) for all real x and y, f(6) = 3 and f'(0) = 10, then f'(6) is :

• 30

• 13

• 10

• 0

Derivative of ${\sec }^{-1}\left(\frac{1}{1 - 2{\mathrm{x}}^2}\right)$ w . r. t ${\sin }^{-1}\left(3\mathrm{x} - 4{\mathrm{x}}^3\right)$ is :

• $\frac{1}{4}$

• $\frac{3}{2}$

• 1

• $\frac{2}{3}$

Let f : $\mathrm{R} \to \mathrm{R}$ be a diiferentiable function Satisfyingf'(3) + f'(2) = 0. Then $\underset{\mathrm{x}\to 0}{\lim }{\left(\frac{1 + \mathrm{f}\left(3 + \mathrm{x}\right) - \mathrm{f}\left(3\right)}{1 + \mathrm{f}\left(2 - \mathrm{x}\right) - \mathrm{f}\left(2\right)}\right)}^{\frac{1}{\mathrm{x}}}$ is equal to :

• 1

• e

• e^{- 1}

• e²

795.

Let f : [- 1, 3] $\to$ R be defined as f(x) = $$\begin{gathered} \left\{\left|\mathrm{x}\right| + \left[\mathrm{x}\right], - 1 \le \mathrm{x} < 1 \\ \mathrm{x} + \left|\mathrm{x}\right|, 1 \le \mathrm{x} < 2 \\ \mathrm{x} +\hspace{0.17em}\left[\mathrm{x}\right], 2 \le \mathrm{x} \le 3\right\} \end{gathered}$$ where [t] denotes the greatest integer less than or equal to t. Then, f is discontinuous at :

• only three points

• only one point

• only two points

• four or more points

If the function f(x) = $$\begin{gathered} \left\{\mathrm{a}|\mathrm{\pi } - \mathrm{x}| + 1, \mathrm{x} \le 5 \\ \mathrm{b}\left|\mathrm{x} - \mathrm{\pi }\right| + 3, \mathrm{x} > 5\right\} \end{gathered}$$ is continuous at x = 5, then the value of a - b is

• $\frac{- 2}{\mathrm{\pi } + 5}$

• $\frac{2}{\mathrm{\pi } + 5}$

• $\frac{2}{\mathrm{\pi } - 5}$

• $\frac{2}{5 - \mathrm{\pi }}$

If $\mathrm{f}\left(\mathrm{x}\right) = \left[\mathrm{x}\right] - \left[\frac{\mathrm{x}}{4}\right], \mathrm{x} \in \mathrm{R}$ , where [x] denotes the greatest integer function, then:

• Both $\underset{\mathrm{x}\to 4^{-}}{\lim }\mathrm{f}\left(\mathrm{x}\right)$ and $\underset{\mathrm{x}\to 4^{+}}{\lim }\mathrm{f}\left(\mathrm{x}\right)$ exist but noot equal

• f is continuous at x = 4

• $\underset{\mathrm{x}\to 4^{-}}{\lim }\mathrm{f}\left(\mathrm{x}\right)$ exist but $\underset{\mathrm{x}\to 4^{+}}{\lim }\mathrm{f}\left(\mathrm{x}\right)$ does not exist

• $\underset{\mathrm{x}\to 4^{+}}{\lim }\mathrm{f}\left(\mathrm{x}\right)$ exist but $\underset{\mathrm{x}\to 4^{-}}{\lim }\mathrm{f}\left(\mathrm{x}\right)$ does not exist

If the function f defined on $\left(\frac{\mathrm{\pi }}{6}, \frac{\mathrm{\pi }}{3}\right)$ by f(x) = $$\begin{gathered} \left\{\frac{\sqrt{2}\cos \left(\mathrm{x}\right) - 1}{\cot \left(\mathrm{x}\right) - 1}, \mathrm{x} \ne \frac{\mathrm{\pi }}{4} \\ \mathrm{k}, \mathrm{x} = \frac{{\displaystyle \mathrm{\pi }}}{{\displaystyle 4}}\right\} \end{gathered}$$ is continuous, then k is equal to :

• 2

• $\frac{1}{2}$

• $\frac{1}{\sqrt{2}}$

• 1

Let f(x) = 15 - $\left|\mathrm{x} - 10\right|$ ; x $\in$ R. Then the set of all values of x, at which the function, g(x) = f(f(x) is not differentiable, is:

• {5, 10, 15}

• {10}

• {10, 15}

• {5, 0, 15, 20}

If $$\begin{gathered} \mathrm{f}\left(\mathrm{x}\right) = \left[\frac{\sin \left(\mathrm{p} + 1\right)\mathrm{x} + \sin \left(\mathrm{x}\right)}{\mathrm{x}}, \mathrm{x} < 0 \\ \mathrm{q}, \mathrm{x} = 0 \\ \frac{\sqrt{{\mathrm{x}}^2 + \mathrm{x}} - \sqrt{\mathrm{x}}}{{\mathrm{x}}^{{\displaystyle \raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}}, \mathrm{x} > 0\right] \end{gathered}$$ is continuous at x = 0, then the ordered pair (p, q) is equal to :

• $\left(- \frac{1}{2}, \frac{3}{2}\right)$

• $\left(- \frac{3}{2}, - \frac{1}{2}\right)$

• $\left(\frac{5}{2}, \frac{1}{2}\right)$

• $\left(- \frac{3}{2}, \frac{1}{2}\right)$