Let f R → R : be differentiable at c ∈ R and f(c) = 0. If g(x) = fx, then at x = c , g is
not differentiable
differentiable if f'(c) = 0
not differentiable if f'(c) = 0
differentiable if f'(c) ≠ 0
B.
g'x = fxfxf'xIf f'(c) = 0 then g'(c+) = g'c- = 0Thus, g differentiable if f'(c) = 0
If f(x) is continuous on - π, π, where
fx = - 2sinx, for - π ≤ x ≤ - π2αsinx + β, for - π2 < x < π2cosx, for π2 ≤ x ≤ π
then α and β are
- 1, - 1
1, - 1
1, 1
- 1, 1
If f(x) = log1 - 3x1 + 3x, for x ≠ 0k, for x = 0 continuous at x = 0, then k is equal to
- 2
2
1
- 1
If x = log1 + t2 and y = t - tan-1t. Then, dydx is equal to
ex - 1
t2 - 1
ex - 12
ex - y
ddxseccos-1x8 is equal to
18
- 18
8x2
- 8x2
If f(x) = 1 + cos2x2, then f'π2 is
π6
- π6
16
If y = asin3θ and x = acos3θ, then at θ = π3, dydx is equal to
- 3
- 13
3
∆2y0 is equal to
2y2 - 2y1 - y0
y2 - 2y1 - y0
2y2 - 2y1 + y0
y2 - 2y1 + y0
∆23ex is equal to
3ex
3(h - 1)ex
3(eh - 1)2ex
None of the above
The value of ∆2Ex2 at the interval h = 1 is
0
4