The point/points of discontinuity of the function f(x) = x&n

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 Multiple Choice QuestionsMultiple Choice Questions

1001.

One root of the equation x2 - 4x+ 1 = 0 is between 1 and 2. The value ofthis root using Newton-Raphson method will be

  • 1.775

  • 1.850

  • 1.875

  • 1.950


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1002.

The point/points of discontinuity of the function f(x) = x + 3,     if x  - 3- 2x,         if - 3 < x < 36x + 2,      if x  3 is/are

  • 3, - 3

  • 3

  • - 3

  • None of these


B.

3

We have,fx = x + 3,     if x  - 3- 2x,         if - 3 < x < 36x + 2,      if x  3For continuity at x = - 3limx- 3-fx = limx- 3-x + 3                      = - 3  + 3 = 6 limx- 3+fx = limx- 3+- 2x = - 2- 3 = 6 f(x) is continuous at x = - 3For continuity at x = 3     limx3-fx = limx3-- 2x = - 23 = - 6     limx3-fx = limx3+6x + 2 = 63 + 2 = 20 limx3+fx  limx3+fx Hence, f(x) is discontmuous of x = 3


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1003.

The value of ddxsintan-1ex at x = 0  is

  • 0

  • - 2

  • - 122

  • - 12


1004.

If f(x) = x2 - 10x + 25x2 - 7x + 10 and f is continuous at x = 5, then f(5) is equal to

  • 0

  • 5

  • 10

  • 25


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1005.

If h(x) = xxx, then at x = 1, h'xhx is equal to

  • h(x)

  • 1hx

  • 1 + loghx

  • - loghx


1006.

ddxsin-13x - 4x3 is equal to

  • 34 - x2

  • 31 - x2

  • 14 - x2

  • - 14 - x2


1007.

If f(x) = x2x + a, then f''(a) is equal to

  • 4a

  • 18a

  • 14a

  • 8a


1008.

If u = ex2 - y2, then

  • xux = yuy

  • yux = xyy

  • yux + xuy = 0

  • x2uy + y2ux = 0


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1009.

If u = xy2tan-1yx, then xux + yuy is equal to

  • 2u

  • u

  • 3u

  • 13u


1010.

If: R  R is defined by f (x) = x - [x], where[x] is the greatest integer not exceeding x, then the set of discontinuous of f is

  • the empty set

  • R

  • Z

  • N


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