The coordinates of the vertices of ∆ABC are A(4, 1), B(-3, 2) and C(0, k). Given that the area of ABC is 12 unit2, find the value of k.
Let the given points be A(-5, 4) and B(7, -8).
Here, we have
x1 = -5, y1 = 4
x2 = 6, y2 = -7
Let the co-ordinate of mid-point be P(x, y).