Let the required point be ‘P’ which is on the y-axis, so, its abscissa = 0 and ordinate (say) = y.
Thus co-ordinates of the point P are (0, y).
Let the given points be A(-5, -2) and B(3, 2).
It is given that: AP = BP
Squaring both side, we get
y2 + 4y + 29 = y2 - 4y + 13
⇒ 4y + 4y = 13 - 29
⇒ 8y = -16
⇒ y = -2
Therefore, the required point is (0, -2).