Find the values of x for which the distance between the point P(

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206. Find the values of x for which the distance between the point P(2, -3) and Q(x, 5) is 10 units. 


Given points be P(2, -3) and Q(x, 5).
It is also given that PQ = 10 units
Here, we have x1 = 2, y1 = -3, x2 = x, y2 = 5


Now comma space space PQ space equals space square root of left parenthesis straight x subscript 2 minus straight x subscript 1 right parenthesis squared plus left parenthesis straight y subscript 2 minus straight y subscript 1 right parenthesis squared end root
rightwards double arrow space space space space space space 10 space equals space square root of left parenthesis straight x minus 2 right parenthesis squared plus left parenthesis 5 plus 3 right parenthesis squared end root
Squaring both sides, we get


Given points be P(2, -3) and Q(x, 5).It is also given that PQ = 10 un


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Fig. 7.28.
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