In what ratio does the point divides the line segment joining the points P(2, -2) and Q(3, 7)? Also find the value of y.
The coordinates of the point P dividing the line segment joining the points A(1, 3) and B(4, 6) in the ratio 2 : 1 are
( 2, 4 )
( 3, 5 )
( 4, 2 )
( 5, 3 )
If the coordinates of the one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (-2, 5), then the coordinates of the other end of the diameter are:
( -6, 7)
( -6, -7)
( 6,7)
( -6, -7)
If a point A(0, 2) is equidistant from the points B(3, p) and C(p, 5) then find the value of p.
It is given that the point A(0, 2) is equidistant from the points B(3, p) and C(p, 5).
So, AB = AC AB2 = AC2
Using distance formula, we have
( 0 - 3 )2 + (2 - p )2 = ( 0 - p )2 = ( 2 - 5 )2
9 + 4 + p2 - 4p = p2 + 9
4 - 4p = 0
p = 1
Hence, the value of p = 1.
A point P divides the line segment joining the points A(3,-5) and B(-4, 8) such that . If P lies on the line x + y = 0, then find the value of K.
If the vertices of a triangle are (1, -3), (4, p) and (-9, 7) and its area is 15 sq. units, find the value (s) of p.