∵ ∆PQR is an equilateral triangle
∴ PQ = PR = QR
⇒ PQ = QR
⇒ PQ = 4
OQ = 2
In right triangle POQ,
OP2Â + OQ2Â = PQ2Â |By Pythagoras Theorem
⇒ OP2 + (2)2 = (4)2
Find the co-ordinates of a point:
(i) Â Â Â whose ordinate is 6 and lies on y-axis.
(ii) Â Â Â whose abscissa is -3 and lies on x-axis.
In which quadrant, can a point have:
(i) Â Â Â abscissa equal to its ordinate
(ii) Â Â ordinate equal in magnitude to abscissa
(iii) Â Â ordinate equal and opposite of abscissa
(iv) Â Â Â abscissa twice that of the ordinate.
(i) Â Â Â The abscissa and the ordinate of the point B are _ _ _ and _ _ _, respectively. Hence the coordinates of B are (_ _, _ _).
(ii) Â Â Â The x-coordinate and the y-coordinate of the point M are _ _ _ and _ _ _, respectively. Hence the coordinates of M are (_ _ _, _ _ _).
(iii) Â Â Â The x-coordinate and the y-coordinate of the point L are _ _ _ and _ _ _, respectively. Hence the coordinates of L are (_ _, _ _).
(iv) Â Â Â The x-coordinate and the y-coordinate of the point S are _ _ _ and _ _ _, respectively. Hence the coordinates of S are (_ _, _ _).
In which quadrant do the given points lie?
(a) (2, -1) Â Â Â (b) (-1, 7)
(c) (-2, -3) Â Â Â (d) (4, 5)