The number of solutions of the system of equations 2x + y - z = 7, x - 3y + 2z = 1 and x + 4y - 3z = 5 is
0
1
2
3
If = 0, then x is equal to
0
- 10
3
None of these
B.
- 10
Given,
On applying , in each determmant, we can take out (x +10) common
Then, we get x + 10 = 0
For the equations x + 2y + 3z = 1, 2x + y + 3z = 2 and 5x + 5y + 9z = 4
there is only one solution
there exists infinitely many solution
there is no solution
None of the above