Verify that the function y = e–3x is a solution of the differ

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 Multiple Choice QuestionsShort Answer Type

21.

Determine the order and degree of the differential equation:
square root of straight x fraction numerator straight d to the power of 4 straight y over denominator dx to the power of 4 end fraction plus 5 open parentheses dy over dx close parentheses squared space equals 2 straight y squared minus straight x

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 Multiple Choice QuestionsMultiple Choice Questions

22. The degree of the differential equation open parentheses fraction numerator straight d squared straight y over denominator dx squared end fraction close parentheses cubed plus open parentheses dy over dx close parentheses squared plus sin open parentheses dy over dx close parentheses plus 1 space space equals space 0 is
  • 3

  • 2

  • 1

  • 1

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23. The degree of the differential equation 2 straight x squared fraction numerator straight d squared straight y over denominator dx squared end fraction minus 3 dy over dx plus straight y space equals space 0  is
  • 2

  • 1

  • 0

  • 0

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 Multiple Choice QuestionsShort Answer Type

24. Verify that y = A cor x – B sin x is a solution of the differential equation
fraction numerator straight d squared straight y over denominator dx squared end fraction plus straight y space equals space 0.
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25. Verify that the function y = a cos x + b sin x, where a, b ∊ R is a solution of the differential equation fraction numerator straight d squared straight y over denominator dx squared end fraction plus straight y space equals space 0.
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 Multiple Choice QuestionsLong Answer Type

26. Verify that y - 3 cos (log x) + 4 sin (log x) is a solution of the differential equation straight x squared fraction numerator straight d squared straight y over denominator dx squared end fraction plus straight x dy over dx plus straight y space equals space 0.
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 Multiple Choice QuestionsShort Answer Type

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27. Verify that the function y = e–3x is a solution of the differential equation fraction numerator straight d squared straight y over denominator dx squared end fraction plus dy over dx minus 6 straight y space equals space 0


                  straight y space equals space straight e to the power of negative 3 straight x end exponent                                                                      ...(1)
therefore         dy over dx space equals space straight e to the power of negative 3 straight x end exponent. space left parenthesis negative 3 right parenthesis space space space space space space space or space space space space space dy over dx equals negative 3 straight e to the power of negative 3 straight x end exponent                ...(2)

         fraction numerator straight d squared straight y over denominator dx squared end fraction equals negative 3 space straight e to the power of negative 3 straight x end exponent. space left parenthesis negative 3 right parenthesis space space space or space space space fraction numerator straight d squared straight y over denominator dx squared end fraction space equals space 9 straight e to the power of negative 3 straight x end exponent                  ...(3)
L.H.S. = fraction numerator straight d squared straight y over denominator dx squared end fraction plus dy over dx minus 6 straight y space equals space 9 straight e to the power of negative 3 straight x end exponent minus 3 straight e to the power of 3 straight x end exponent minus 6 straight e to the power of negative 3 straight x end exponent space space space space space open square brackets because space of space left parenthesis 1 right parenthesis comma space left parenthesis 2 right parenthesis comma space left parenthesis 3 right parenthesis close square brackets
            = 0 - R.H.S.
therefore space space space straight y space equals straight e to the power of negative 3 straight x end exponent  is a solution of the differential equation
                        fraction numerator straight d squared straight y over denominator dx squared end fraction plus dy over dx minus 6 straight y space equals space 0

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28. Show that the function y = ae2X + be–x is a solution of differential equation fraction numerator straight d squared straight y over denominator dx squared end fraction minus dy over dx minus 2 straight y space equals space 0.
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29. In the following, verify that the given functions, (explicit or implicit) is a solution of the corresponding differential equation:
straight y space equals space straight e to the power of straight x plus 1                    :    straight y to the power of straight n minus straight y apostrophe space equals space 0
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30. In the following, verify that the given functions, (explicit or implicit) is a solution of the corresponding differential equation:
straight y space equals space straight x squared plus 2 straight x plus straight C                              :     straight y apostrophe minus 2 straight x minus 2 space equals space 0
                    
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